Insecure exceptions - Empty or no catch - Python
Need
Proper exception handling and error management
Context
- Usage of Python 3.0+ for developing Python applications
- Usage of Django for building web applications with Python
Description
Insecure Code Example
from django.http import HttpResponse
from .models import MyModel
def my_view(request):
try:
my_model = MyModel.objects.get(pk=1)
except:
pass
return HttpResponse(my_model)
The above code shows a Django view function `my_view` that tries to retrieve an instance of `MyModel` with a primary key of `1`. The vulnerability lies in the `except:` block where an exception is silently ignored with the `pass` statement. This is a clear example of an empty `catch`. If the `get` method throws an exception (for example, if there is no `MyModel` instance with a primary key of `1`), the `except:` block will catch it and do nothing. This means that the `my_model` variable will not be defined, and the function will still try to return it as a `HttpResponse`. This will result in an `UnboundLocalError` being raised, which is not being handled anywhere. This can cause the application to become temporarily or permanently unavailable, depending on how the application is structured. Furthermore, silently ignoring exceptions is a bad practice, because it makes debugging more difficult and can hide underlying issues that might be critical.
Steps
- Identify the specific exceptions that the code might throw and catch those specific exceptions instead of using a generic catch-all exception handler.
- Remove the 'pass' statement in the catch block and replace it with appropriate error handling code. This could include logging the error, returning an error response, or re-throwing the exception after some cleanup.
- Ensure that the application can continue to function in a meaningful way even when an exception is caught. This could involve setting default values, retrying the operation, or informing the user about the error.
- Consider using the 'finally' block to ensure that any necessary cleanup code is always executed, regardless of whether an exception was thrown or not.
Secure Code Example
from django.http import HttpResponse, Http404
from .models import MyModel
import logging
def my_view(request):
my_model = None
try:
my_model = MyModel.objects.get(pk=1)
except MyModel.DoesNotExist:
logging.error('MyModel with pk=1 does not exist')
raise Http404("No MyModel matches the given query.")
except Exception as e:
logging.error('An error occurred: ' + str(e))
return HttpResponse('An error occurred: ' + str(e), status=500)
return HttpResponse(my_model)
The updated code now handles exceptions in a more secure and robust manner. Firstly, instead of using a generic catch-all exception handler, we are now catching specific exceptions that might be thrown by the `MyModel.objects.get(pk=1)` operation. This includes the `MyModel.DoesNotExist` exception, which is thrown when no `MyModel` instance with `pk=1` exists, and a generic `Exception`, which will catch any other exceptions that might be thrown. Secondly, we have removed the `pass` statement in the catch block and replaced it with appropriate error handling code. In the case of `MyModel.DoesNotExist`, we log the error and raise a `Http404` exception, which will result in a 404 error being returned to the client. In the case of a generic `Exception`, we log the error and return a 500 error response to the client. Thirdly, we ensure that the application can continue to function in a meaningful way even when an exception is caught. If an exception is thrown, an error response is returned to the client, informing them about the error. Finally, although not shown in the code, you could consider using a `finally` block to ensure that any necessary cleanup code is always executed, regardless of whether an exception was thrown or not. This could include closing database connections, releasing resources, etc.
References
Last updated
2023/09/18